A consolidation test is being performed on a 3.5 inch diameter and saturated soi

Question

A consolidation test is being performed on a 3.5 inch diameter and saturated soil specimen that had an initial height of 0.750 in. and an initial moisture content of 38.8%.

(a). Using Gs = 2.69 compute the initial void ratio, eo

(b). At a certain stage of the test, th enormla load P was 300lb. After consolidation at this load was completed, the specimen height was 0.690 inch. Compute ?'z  (expressed in lb/ft^2), ez , and e.

Explanation / Answer

initial water content, w0 = 38.8 % = 0.388 Initial height, H0 = 0.75 inch diameter of loaded area, d = 3.5 inch degree of saturation, S = 1 a). Gs = 2.69 initial void ratio, e0 = (w0*Gs)/S = (0.388*2.69)/1 = 1.04372 b). final height = 0.69 inch total settlement, h = 0.75 - 0.69 = 0.06 inch h/H0 = change in void ratio/(1+e0) => change in void ratio = (0.06/0.75)*(1+1.04372) = 0.1634976 final void ratio = e0 - change in void ratio = 1.04372 - 0.1634976 = 0.8802224 effective overburden pressure, P2 = normal load/loaded area = 300/(pi*d^2/4) lb/ft^2 => P2 = 300/[{3.14*(3.5/12)^2}/4] = 0.06678 lb/ft^2

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