Scientists want to place a 3500.0 kg satellite in orbit around Mars. They plan t

Question

Scientists want to place a 3500.0 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.6 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kg rmars = 3.397 x 106 m G = 6.67428 x 10-11 N-m2/kg2 1) What is the force of attraction between Mars and the satellite? 2) What speed should the satellite have to be in a perfectly circular orbit? 3) How much time does it take the satellite to complete one revolution?

Explanation / Answer

a)F=GMm/r2=6.67428*10-11*6.4191*1023*3500/(2.6*3.397*106)2=1922.2N

b)mv2/r=F

v=sqrt(Fr/m)=2202.4m/s

c)T=2r/v=25197s=7.00 hours

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