Out of Retries Do not round intermediate calculations; however, for display purp

Question

Out of Retries Do not round intermediate calculations; however, for display purposes, report intermediate steps rounded to four significant figures. Give your final answer(s) to four significant figures. An airplane is flying straight and level at a speed nu0 = 130 mph, and with a constant time rate of increase of speed = 21 ft/s2, when it starts to climb along a circular path with a radius of curvature p = 1,900 ft. The airplane maintains constant for about 30 s. Determine the acceleration of the airplane 25 s after the start of the climb and express the result in the Cartesian component system shown.

Explanation / Answer

Final velocity after 25 s = 130 + (21*25) = 655 mph

Distance traveled in 25 s = 130 + (21 * 25^2) = 13255 miles

Thus, its location on the circle : R * = 13255

=> = 13255 / 1900 = 6.976315 radians = 399.713406 degrees (from the start of the loop)

=> = 399.713406 - 360 = 39.713406 degrees (from the start of the loop)

Thus the acceleration is given as:

a = [-{(v^2) / R} * sin() ] i + [ { {(v^2)/R} *cos() } - g ] j,

where R : radius 1900 ft

          v = 655 mph = 655 *1.46667 = 960.66885 ft/s

          g = 32.1740 ft /s2

a = (-155.1777 i + 154.6494 j) ft/s^2

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.