A particle moves along the x axis. It is initially at the position 0.150 m, movi

Question

A particle moves along the x axis. It is initially at the position 0.150 m, moving with velocity 0.150 m/s and acceleration -0.400 m/s2. Suppose it moves with constant acceleration for 6.00 s. (a) Find the position of the particle after this time. m (b) Find its velocity at the end of this time interval. m/s Next, assume it moves with simple harmonic motion for 6.00 s and x = 0 is its equilibrium position. (Assume that the velocity and acceleration is the same as in parts (a) and (b).) (c) Find its position. m (d) Find its velocity at the end of this time interval. m/s

Explanation / Answer

xi=starting point=0.15 xe=ending point= vi=initial velocity=0.150 ve=ending velocity= a=0.40 m/s^2 t=6.00 s xe=xi+vit+1/2at^2 then ve=vi+at

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