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Unpoloarized light is passed through a set of n polarizers. The first polarizer

ID: 1904889 • Letter: U

Question

Unpoloarized light is passed through a set of n polarizers. The first polarizer is arranged with the polarizing slits aligned vertically, and the last polarizer of the set is arranged so its slits are aligned horizontally. Each polarizer in between these 2 polarizers is arranged with its polarizing slits at an angle of ? with respect to the previous one. (In other words, the second polarizer in the set is at an angle of ? with the vertical, the third polarizer is at an angle of 2? with the vertical, the fourth one is at an angle of 3? with the vertical and so forth.) How many total polarizers are required (n = ?) so that the intensity of the light coming out of the last polarizer is 33% of the intensity of light coming into the first polarizer? (Hint: It shouldn

Explanation / Answer

each polarizer drops the intensity by a factor of cos()^2

however the first drops it by a factor of 1/2

so In =0.5* (cos())^(n-1)

you dont have what to use but you should be able to figure out n if you have it by trial and error

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