A rod of length 0.850 m is attached to a pivot at one end. A force F of 2.30 N i

Question

A rod of length 0.850 m is attached to a pivot at one end. A force F of 2.30 N is applied to the end of the bar opposite the pivot. The force makes an angle of 65.0o with the bar. (The ? in the figure is the angle for the "line of action" of the force, which has the same value as the angle between F and the bar.) Calculate the resulting torque due to this force. (Use the left end of the bar as the fulcrum.) What is the torque due to this force if the right end of the bar is used as the fulcrum, and the force is applied at the original position (the right end of the bar)?

Explanation / Answer

the torque is 0.85*2.3*sin65 = 1.772 the torque is zero as the distance between the origin and point of action of force is 0

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