A rod of length 0.850 m long is attached to a pivot at its left end. A force F o

Question

A rod of length 0.850 m long is attached to a pivot at its left end. A force F of 2.30 N is applied to the end of the bar opposite the pivot. The force is applied perpendicular to the bar.

PICTURE: http://www.webassign.net/userimages/jmilton@depaul/torque1.jpg

Calculate the resulting torque due to this force.
_____ N m

I keep getting 0.9775 but it's the wrong answer! I did 0.850/2 to get 0.425. Then I did 0.425(2.3)(sin90) to get 0.9775 but it's not the right answer. I also rounded to 1 and it's incorrect. Someone please help

A rod of length 0.850 m long is attached to a pivot at its left end. A force F of 2.30 N is applied to the end of the bar opposite the pivot. The force is applied perpendicular to the bar.

PICTURE: http://www.webassign.net/userimages/jmilton@depaul/torque1.jpg

Calculate the resulting torque due to this force.
_____ N m

I keep getting 0.9775 but it's the wrong answer! I did 0.850/2 to get 0.425. Then I did 0.425(2.3)(sin90) to get 0.9775 but it's not the right answer. I also rounded to 1 and it's incorrect. Someone please help

Explanation / Answer

According to the question provided we need to find the value of the resultant torque due to the force.

Length = 0.850 m and Force = 2.30 N Theta = 90 deg

T = rFsin theta = 0.850 m * 2.30 N * sin ( 90 ) = 1.955 N-m ===================ANSWER)

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