Two crates connected by a rope lie on a horizontal surface. Crate A has mass and

Question

Two crates connected by a rope lie on a horizontal surface. Crate A has mass and crate B has mass . The coefficient of kinetic friction between each crate and the surface is . The crates are pulled to the right at constant velocity by a.

Two crates connected by a rope lie on a horizontal surface. Crate A has mass and crate B has mass . The coefficient of kinetic friction between each crate and the surface is . The crates are pulled to the right at constant velocity by a. In terms of F vector Mu k , calculate the magnitude of the force mB , and mA ,

Explanation / Answer

constant velocity, so gravity cancels F, giving UkmA+UkmB=||F|| I think the tension is the force pulling the trailing crate and thus depends on their positions. If B is left of A, then it is UkmB. Thus, a weak rope could support pulling in one direction and not the other.

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