A cat dozes on a stationary merry-go-round, at a radius of5.5m from the center o

Question

A cat dozes on a stationary merry-go-round, at a radius of5.5m from the center of the ride. Then the operator turns on the ride and brings it up to its proper turning rate of one complete rotation every6.0s. What is the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding?
A cat dozes on a stationary merry-go-round, at a radius of5.5m from the center of the ride. Then the operator turns on the ride and brings it up to its proper turning rate of one complete rotation every6.0s. What is the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding?

Explanation / Answer

Static friction force=mg

This should provide the centripetal force to the cat to rotate.

mg=m2r

=2/6=1.047/s

*9.81=1.0472*5.5

=0.615

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