A cat dozes on a stationary merry-go-round, at a radiusof 5.9 m from the center

Question

A cat dozes on a stationary merry-go-round, at a radiusof 5.9 m from the center of theride. Then the operator turns on the ride and brings it up to itsproper turning rate of one complete rotationevery 6.1 s. What is the leastcoefficient of static friction between the cat and themerry-go-round that will allow the cat to stay in place, withoutsliding?
I don't knowhow this can be figured out without knowing the mass of the cat. Please show steps.
I don't knowhow this can be figured out without knowing the mass of the cat. Please show steps.

Explanation / Answer

      m2r =mg         =2 r / g       Here, = 2 / T= 2 / 6.1 = 1.03 rad / s                r = 5.9 m     Therefore,      = 0.639

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