where q1 = 6.05 10-9 C, q2 = -2.37 10-9 C, and q3 = 4.95 10-9 C. Using the same
ID: 1899025 • Letter: W
Question
where q1 = 6.05 10-9 C, q2 = -2.37 10-9 C, and q3 = 4.95 10-9 C.
Using the same triangle, find the vector components of the electric force on q1 and the vector's magnitude and direction. (Use the charges given in the Practice It section.)
FInd:
Fx= N
Fy= N
Magnitude= N
Direction = degress (counter clockwise from the + x axis)
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Explanation / Answer
the total force on q1 is F1 = k*q1*q2/r1^2 where r1 = 5 m now the force is F = 1.06*10^-8 N => Fx = - F*cos(36.9) = 8.4*10^-9 N Fy = 6.3*10^-9 N the direction being
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