where r = kT, and A: is Boltzmann\'s constant, 5 is the acceleration at the surf
ID: 1678768 • Letter: W
Question
where r = kT, and A: is Boltzmann's constant, 5 is the acceleration at the surface of the Earth, and m is the mass of a gaseous particle. For the purposes of this problem, we will take T = 300 K, and m = 28.6 mu, ) where mu is one atomic mass unit. This corresponds to the mean molecular mass of the Earth's atmosphere. f(z) is normalized such that Multiply f(z) by the density of the atmosphere at sea level rho(0) = 1.2 kg/m3 = 1.2 10-3gm/cm-3 to find the distribution of atmospheric mass density rho(z) as a function of height, z. What, do you predict for the density of the atmosphere at the top of the stratosphere, at a height of 50 km?Explanation / Answer
b) (z=50km)= (0) *f(z=50km)/(mg/)=(0) * exp(-mg(50km)/) substituting values (0)=1.2 kg m^(-3) T=300,k=1.38*10^(- 16) ergs k^(-1),m=28.6*1.66*10^24 grams (z=50)=0.0043 kg m^(-3)Related Questions
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