A m2 = 4.25 kg mass is connected by a light cord to a m1 = 2.04 kg mass on a smo

Question

A m2 = 4.25 kg mass is connected by a light cord to a m1 = 2.04 kg mass on a smooth surface (see the figure below).
The pulley rotates about a frictionless axle and has a moment of inertia of 0.430 kg* m2 and a radius of 0.292 m. Assuming that the cord does not slip on the pulley, find the acceleration of m1. Answer= 3.68 m/s/s
What is the acceleration of m2?

http://img291.imageshack.us/img291/9084/imagecvi.png

Explanation / Answer

m2g -T1 = m2a T2 = m1a (T1-T2)x r = I x a/r ==> T1-T2 = I x a /r^2 = 5.04a....(1) T1 = 7.08a.....(2) a = 3.676 m/s2 acceleration is same for both..you got it right? what do you want from us to do?

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