A m=1.36E3 kg satellite orbits at radiusR s =2.57*10 7 m about the center of a p

Question

A m=1.36E3 kg satellite orbits at radiusRs=2.57*107 m about the center of a planet ofmass M with a speed of v=3,944 m/s. (Recall U=-GMm/ Rs.So the gravitational potential energy is zero at infinity.G=6.67*10 -11 N*m2/kg2.)

a) What is the value of the mass M of the planet?

b) What is the total mechanical energy (K+U) of thesatellite?
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A m=1.36E3 kg satellite orbits at radiusRs=2.57*107 m about the center of a planet ofmass M with a speed of v=3,944 m/s. (Recall U=-GMm/ Rs.So the gravitational potential energy is zero at infinity.G=6.67*10 -11 N*m2/kg2.)

a) What is the value of the mass M of the planet?

b) What is the total mechanical energy (K+U) of thesatellite?
I will give top score for someone help explained thisquestion...

Explanation / Answer

Mass of the satellite m=1.56 * 10 ^ 3 kg
orbital radius Rs=2.54*107 m Orbital speed v=3,942 m/s Gravitational constant G=6.67*10 -11N*m2/kg2 (a). we know v = [ GM / R s ] from this we find mass of the planet m value (b). Total mechanical energy E = U + K where U = potential energy = -GMm / R s            K = kinetic energy = ( 1/ 2) m v ^ 2 substitue values we get answer

(a). we know v = [ GM / R s ] from this we find mass of the planet m value (b). Total mechanical energy E = U + K where U = potential energy = -GMm / R s            K = kinetic energy = ( 1/ 2) m v ^ 2 substitue values we get answer

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