A 272 kg piano slides 4.14 m down a 27.0° incline and is kept from accelerating
ID: 1883834 • Letter: A
Question
A 272 kg piano slides 4.14 m down a 27.0° incline and is kept from accelerating by a man who is pushing back on it parallel to the incline, as seen in figure below. The effective coefficient of kinetic friction is 0.370. a) Calculate the force exerted by the man. b) Calculate the work done by the man on the piano c) Calculate the work done by the force of gravity. d) Calculate the net work done on the piano
Work Along An Incline Puntos:5 A 272 kg piano slides 4.14 m down a 27.0 incline and is kept from accelerating by a man who is pushing back on it parallel to the incline, as seen in figure below. The effective coefficient of kinetic friction is 0.370 Calculate the force exerted by the man.Explanation / Answer
A)
Force exerted by the person, F = mg sin(theta) = (272 x 9.8) sin(27) = 1210.16 N
B)
Work, W = - Fs = - (1210.16 x 4.14) = - 5010.05 J
C)
Work, Wg = - W = 5010.05 J
D)
Work, W = 0
Comment in case any doubt please rate my answer....
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.