A farm truck moves due east with a constant catches velocity of 9.30 m/\'s on a

Question

A farm truck moves due east with a constant catches velocity of 9.30 m/'s on a limitless, hortsontal stretch of road. A bey nding on the the projectle back of the truck throws a can of sode upward (see figure below) and at the same location on the truck bed, but 11.0m farther down the road. (a) In the frame of reference of the truck, at what angle to the vertical does the boy threw the can? (b) What is the Initial speed of the can relative to the truck? mys (c) what is the shape of the can's trajectory as seen by the boy? O a straight line segment upward and then downward O a symmetric section of a parabola opening downward An observer on the ground watches the boy throw the can and catch it (d) In this observer's frame of reference, describe the shape of the can's path O a straight line segment upward and then downward a symmetric section of a parabola opening downward (e) In this observer's frame of reference, determine the initial velocity of the can. magnitude direction m/s e above the horizontal eastward line

Explanation / Answer

Considering horizontal motion,

x = vot + (0.5)at^2

11 = (9.3) t + 0

t = 1.18 s

(a)

He must throw straight up, at 0 degrees to the vertical.

(b)

For the free fall of the can,

yf = vyit + (1/2)ayt^2

0 = 0 + vyi (1.18) - (1/2)(9.8) (1.18)^2

vyi= 5.81 m/s

(c)

The boy sees the can always over his head, traversing a straight line segment upward and then downward.

(d)

The ground observer sees the can move as a projectile on a symmetric section of a parabola opening downward.

(e)

Initial velocity

vo = sqrt (9.30^2+ 5.81^2) = 10.97 m/s north

Direction = arctan(5.81/9.3) = 32 above the horizontal

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