A farm truck catches the projectile at the same location on the truck bed, but 1

Question

A farm truck catches the projectile at the same location on the truck bed, but 18.0 m farther down the road. moves due east with a constant velocity of 12.00 m/s on a limitless hortzontal stretch of road. A boy riding on the back of the truck throws a can of soda upward (see figure) and (o) In the freme of referance of the truck, at what angle to the vertical does the boy throw the can? ) What is the initial speed of the can relative to the truck? (c) Whet is the shape of the can's trajectory as seen by the bey? a straight line segment upward and then donnward a symmetric section of a parabola opening downward n observer on the ground watches the bey throw the can and catch it (d) In this observer's frame of reference, describe the shape of the can's path symmetric section of a parabola opening downward a straight line segment upward and then downward (e11n this observer·fra me of reference, determine the initial velocity of the can. magnitude direction * above the horizontal

Explanation / Answer

Time to cross 18 m with a speed of 12m/s is 18/12 = 1.5 s.
The vertical velocity of the can with respect to the truck is
v = gt/2 = (9.8*1.5)/2 = 7.35 m/s
Resultant velocity of the can with respect to the road
= (7.35^2 + 12^2) =14.07 m/s
tan = 7.35/12
= 31.5°
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(a) since he catches the projectile at the same location on the truck bed, answer is vertical or angle zero to the vertical.

b) the initial speed of the can relative to the truck is 7.35 m/s vertically up relative to the truck.

c) a straight line upward

d) a symmetric parabola

e) In this observer's frame of reference, the initial speed is 14.07 m/s at an angle of 31.5° to the horizontal.

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