A farm truck moves due east with a constant velocity of 11. 00 m/s on a limitles

Question

A farm truck moves due east with a constant velocity of 11. 00 m/s on a limitless, horizontal stretch of road. A boy riding on the back of the truck throws a can of soda upward (see figure below) and catches the projectile at the same location on the truck bed, but 19. 0 m farther down the road. In the frame of reference of the truck, at what angle to the vertical does the boy throw the can? degree What is the initial speed of the can relative to the truck? m/s What is the shape of the can's trajectory as seen by the boy? a straight line segment upward and then downward a symmetric section of a parabola opening downward An observer on the ground watches the boy throw the can and catch it. In this observer's frame of reference, describe the shape of the can's path. a straight line segment upward and then downward a symmetric section of a parabola opening downward In this observer's frame of reference, determine the initial velocity of the can magnitude m/s direction degree above the horizontal

Explanation / Answer

t = 19/11 s v cos t * t = 19 v*cos t = 11 m/s 0 = v* sin t*19/11 - 4.9*(19/11)^2 v* sin t = 8.4636 so tan t = 0.769 t = 37.575 degrees a) zero b)it is v sin t = 8.4635 m/s c)a straight line upward and downward d)a symmetric section of parabola opening downward e) v = 13.879 m/s direction = 37.575 degrees above horizontal

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