Two identical point charges (+2.5 109 C) are fixed in place, separated by 0.46 m

Question

Two identical point charges (+2.5 109 C) are fixed in place, separated by 0.46 m (see the figure). (Assume that the +x-axis is to the right.)

Midpoint 8 4A Concepts (i) The electric field is a vector and has a direction. At the midpoint, what are the directions of the individual electric-field contributions from qA and qB? QA I Select Ge Select (ii) Is the magnitude of the net electric field at the midpoint greater than, less than, or equal to zero? O greater than zero less than zero equal to zero ii) Is the total electric potential at the midpoint positive, negative, or zero? O positive O negative zero (iv) Does the electric potential have a direction associated with it? Explain O No, the electric potential is zero O No, the electric potential is a scalar O Yes, along the -x-axis O Yes, along the +x-axis Calculations: Find the electric field and the electric potential at the midpoint of the line between the charges qA and qB. (For the electric field, enter the magnitude.) electric field electric potential N/C

Explanation / Answer

(i) As both charges are positive, the electric field points away from both charges.

Therefore, for qA, the electric field points to the right and for qB , the electric field points to the left.

(ii) As both charges are of same magnitude and point in opposite direction, the electric field will be equal to zero at the midpoint

(iii) Potential will be positive as charges are positive

(iv) No, Electric potential is a scalar quantity

(v) Electric field = 0 N/C

Potential, V = 2kq/r = 2*9e9*2.5e-9 / 0.23

Potential = 195.65 V

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