The rolling resistance of a vehicle can be calculated as F-mg where m is the mas

Question

The rolling resistance of a vehicle can be calculated as F-mg where m is the mass of the vehicle, g is the acceleration due to gravity. and c, is the coefficient of rolling resistance. How much more fuel is needed for a van to overcome rolling resistance than a car if the mass of the vehicles is man-3493 kg and m 1330 kg and each car drives a distance of 252 km? Assume that Cr-0.02, that the energy density of gasoline is 36000 kn, and that the efficiency of the engine in each vehicle is 25%. Select one: O a. 3.0L O b. No different because the travel distance is the same. O c. 3.7 L d. 1.0L

Explanation / Answer

W = Fs / n

F force ; s distance ; n efficiency

W = cmgs / n

W car = 0.02 x 1330 x 9.8 x 252

= 65691 kJ

W van = 0.02 x 3493 x 9.8 x 252

= 172526 kJ

difference = 106835 kJ

gas = 106835 / 36000

= 2.97 L

= 3 litres

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