Parallel Dielectric 006 (part 1 of 2) 10.0 points A capacitor is constructed fro

Question

Parallel Dielectric 006 (part 1 of 2) 10.0 points A capacitor is constructed from two square metal plates. A dielectric K-1.29 fills the upper half of the capacitor and a dielectric K-6.1 fills the lower half of the capacitor. Neglect edge effects. dielectric 1.29 constant top dielectric bottom constant 1 0.51 mm Calculate the capacitance C of the device Correct answer: 6568.9 pF 007 (part 2 of 2) 10.0 points Qt What is the ratio of pla te charge in bottom the top-half region to that in the bottom-hal region. Correct answer: 0.211475

Explanation / Answer

Capacitance of upper portion

C1= k epsilon_not* A/d= *1.29*8.85*10^-12*0.32*0.16/(0.51*10^-3)= 1.146*10^-9 F

Capacitance of lower portion

C2= 6.1*8.85*10^-12*0.32*0.16/(0.51*10^-3)= 5.42*10^-9

Net capacitance of circuit

C= c1+c2= 6.566 *10^-9 F= 6566 pF

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Charge is directly proportional to capacitance if voltage keep constant

Q1/Q2= C1/C2= 1.147/5.42= 0.211

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Comment in case any doubt.. good luck

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