Bullfrogs can jump up to 6.5 meters along the ground. We know this because there

Question

Bullfrogs can jump up to 6.5 meters along the ground. We know this because there is an annual frog jumping competition in California. In the air, frogs behave just like any other object and obey the equations of motion for projectiles examined in class. (a) A bullfrog jumps into the air with a launch angle of 25 degrees above the horizontal. Calculate the launch speed (i.e. the magnitude of the launch velocity) if the time between take-off and landing is 0.55s. This frog does not jump 6.5 meters! (3 points) Assume that the frog lands at the same height that it takes off from. Start by sketching the trajectory through the air and identify the equations of motion that might be useful in solving the problem. (b) The frog accelerates to the launch speed from rest, by rapidly extending its back legs. It can accelerate so long as its back feet are on the ground. If the back feet remain on the ground while the legs extend by 12 cm, calculate the acceleration of the frog in the launch direction. (3 points) Now that we’ve talked about Newton’s laws in class we can look at some of the details of how the jump might be initiated. (c) Calculate the force needed to generate this acceleration if the mass of the frog is 0.25 kg. (2 Points) The above calculation provides a macroscopic description of the frog’s ability to generate a force. At the microscopic scale the force is generated by the motor protein, myosin, as it walks (yes, myosin does walk!) along cytoskeletal actin filaments during muscle contraction. Measurements made of the force generated by individual myosin proteins suggest that each myosin generates about 1.4 pico-Newtons of force (where 1 picoNewton = 1×10-12 Newtons). (d) Calculate the minimum number of myosin motor proteins working together needed to generate the force produced by the frog’s legs. (2 points)

I just need part d) please!

Explanation / Answer

Part (d) F = ma ;

This the the force that has been calculated in part (c)

1 myosin generates 1.4 x 10^-12 N of force, so the number of Myosin will be:

n = F/(1.4 x 10^-12)

So, you just have to divide the fprce F obtained in part C with the force generated by one myosion that is 1.4 x 10^-12 N and u wil get the number of myosin.

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