ysics question | Chegg brummer justin@yahoo.c x tate.instructure.com/courses/622
ID: 1878134 • Letter: Y
Question
ysics question | Chegg brummer justin@yahoo.c x tate.instructure.com/courses/62274/assignments/697931 Question 7 Your answer is partially correct. At t1-3.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is ai (3.00 m/s2)i+(7.00 m/s2)j At t2 7.00 s (less than one period later), the acceleration is 2 (7.00 m/s2) (3.00 m/s2) The period is more than 4.00 s. What is the radius of the circle? Number Units 7.61577 e Textbook and Media Hint Draw a circle centered on the origin. Locate the particle when it has the first given acceleration vector. Then locate it when it has the scond one. In terms of a circumference, how far does the particle move between those locations? PreviousExplanation / Answer
Given,
a1 = 3 i + 7j
a2 = 7i - 3j
a = sqrt (3^2 + 7^2) = 8.37 m/s^2
The object is moving 3/4 of a circle within the given time.
t2 - t1 = 7 - 3 = 4 s
the dot product comes to be 0, so angle = pi/2
since the particle is moving in CCW direction, theta = 2 pi - pi/2 = 3 pi/2 = 4.71
v = theta r/t
a = v^2/r
r = a t^2/theta^2
r = 8.37 x 4^2/4.71^2 = 6.04 m
Hence, r = 6.04 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.