Part A Coulomb\'s law for the magnitude of the force F between two particles wit

Question

Part A Coulomb's law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is What is the net force exerted by these two charges on a third charge q3 54.0 nC placed between g and q2 at 31.110 m? Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures. where K, and eo 8.854x 10-2 C/(N-m2) is the permittivity of free space Consider two point charges located on the x axis: one charge, g-10.0 nC, is located at z1 1.745 m; the second charge, 2 37.5 nC, is at the origin (0.0000) View Available Hint(s) Force on 9,3= Submit Provide Feedback

Explanation / Answer

q1 exerts a force of attraction on q3

force exerted by q1 on q3 is along -x direction

F 1on3 = -k*q1*q3/(x3-x1)^2

F 1on3 = -(1/(4*pi*8.854*10^-12))*(10*10^-9*54*10^-9/(-1.11-(-1.1745))^2) = 0.0011666079963 N

q2 exerts a force of repulsion on q3

force exerted by q1 on q3 is along -x direction

F 2on3 = -k*q2*q3/(x3-x2)^2

F 2on3 = -(1/(4*pi*8.854*10^-12))*(37.5*10^-9*54*10^-9/(-1.11-0)^2) = -1.477*10^-5 N

F3 = F1 on 3 + F2 on 3 = -0.00102 N

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