Part A Consider a uniformly charged thin ring of radius R and charge Q . What is
ID: 1586954 • Letter: P
Question
Part A
Consider a uniformly charged thin ring of radius R and charge Q . What is the charge density on the ring?
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Part B
A disc of radius R carries charge Q distributed uniformly on its surface. Find an expression for a differential charge element in the disc, in cylindrical polar coordinates. Use r as your radial coordinate and as your azimuthal coordinate.
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Part C
A disc of radius R caries charge density =ar2 , where a is a constant and r is the distance between an arbitrary point on the disc and the disc's center. What is the total charge on the disc?
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Part D
Now consider a thin ring of radius R that carries charge density =0cos(/4) , where 0 is a constant. What is the total charge on the ring?
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=
Explanation / Answer
A)
charge density = total charge /length = Q/(2*pi*R)
B)
dq = elemental area*density
dq = 2*pi*r*dr*Q/(pi*R^2)
dq = (2*r*dr*Q)/R^2
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C)
small charge dq = 2*pi*r*dr*sigma*r^2
dq = sigma*2*pi*r^3*dr
Q = integration dq
Q = sigma*2*pi*r^4/4 from r=0 to r = R
Q = (1/2)*sigma*pi*R^2
(D)
dq = L*ds = Lo*cos(pi/4)*ds
Q = integration dq
Q = Lo*cos(pi/4)*2*pi*R
Q = 2*pi*R*Lo*cos(pi/4)
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