A block of weight wt 1 = 444 N sits on a frictionless table of mass 119 kg. The

Question

A block of weight wt1 = 444 N sits on a frictionless table of mass 119 kg. The block is connected via frictionless pulley to a hanging block with weight wt2 = 190 N. (Ignore any minor frictional effects and assume the pulley to be massless.)

1)

What is the magnitude of the acceleration of the block on the table?

|a1| =

m/sec2  

2)

What is the magnitude of the acceleration of the block hanging over the side?

|a2| =

m/sec2  

3)

What is the tension in the rope connecting the two masses?

T =

N  

Explanation / Answer

The acceleration (magnitude) of each block is the same

Now sum forces about w1

T = wt1/g*a

Summing forces about the hanging block wt2 - T = wt2/g*a

or T = wt2 - wt2/g*a

Therefore equating both of these we get

wt1/g*a = wt2 - wt2/g*a

or (wt1/g + wt2/g)*a = wt2

so a = wt2/(wt1/g + wt2/g) = 190/(444/9.8 + 190/9.8) = 2.93m/s^2

c) T = wt1/g*a = 444/9.8*2.93 = 132.746N

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