The position of an object as a function of time is given by x(t) = at^4 + bt, wh

Question

The position of an object as a function of time is given by x(t) = at^4 + bt, where a = 1.40 m/s^4, b = 2.00 m/s.
a. Find the instantaneous velocity of the object at t = 3.00 s.
b. Find the instantaneous acceleration at t = 3.00 s. The position of an object as a function of time is given by x(t) = at^4 + bt, where a = 1.40 m/s^4, b = 2.00 m/s.
a. Find the instantaneous velocity of the object at t = 3.00 s.
b. Find the instantaneous acceleration at t = 3.00 s.
a. Find the instantaneous velocity of the object at t = 3.00 s.
b. Find the instantaneous acceleration at t = 3.00 s.

Explanation / Answer

x = 1.40 t^4 + 2 t

(A) v = dx/dt = 5.6 t^3 + 2

putting t = 3 s

v = 153.2 m/s

(B) a = dv/dt = 16.8 t^2

at t = 3s

a = 151.2 m/s^2

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