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(8c4p2) A watermelon has the following coordinates: x--5.0 m, y-3.0 m, and z-0.0

ID: 1872583 • Letter: #

Question

(8c4p2) A watermelon has the following coordinates: x--5.0 m, y-3.0 m, and z-0.0 m. Find its position vector in terms of the vector's magnitude and orientation. Magnitude? Submit Answer Tries 0/8 Angle (ino deg) as measured counterclockwise from the x-axis Submit Answer Tries 0/8 Sketch the vector on a right-handed coordinate system. If the watermelon is moved to the x y z coordinates 5.0 m, 0.0 m, 0.0 m), what is its displacement in unit-vector notation? i-component? Submit Answer Tries 0/8 component? Submit Answer Tries 0/8 k-component? Submit Answer Tries 0/8 What is its displacement in terms of a magnitude? Submit Answer Tries 0/8 What is its displacement in terms of orientation? Submit Answer Tries 0/8

Explanation / Answer

magnitude = sqrt(x^2 + y^2 + z^2)

= 5.8 m .....Ans


direction = 180 - tan^-1(3/5) = 149 deg .....Ans


i - compo = 5 m ....Ans

j -compo = 0

k - compo = 0


displacement magnitude = 5 m

direction angle (orientation) = 0 deg