(8c4p37) A ball is shot from the ground into the air. At a height of 8.7 m, the

Question

(8c4p37) A ball is shot from the ground into the air. At a height of 8.7 m, the velocity is observed to be -(80)i + (6.3)j in meters per second (i horizontal, j upward). To what maximum height will the ball rise? You are correct Previous Tries Your receipt no. is 165-4763) What will be the total horizontal distance traveled by the ball? Submit Answer Incorrect. Tries 4/12 Previous Tries What is the velocity of the ball (magnitude and direction) the instant before it hits the ground? That is what is its i-component? Submit Answer Tries 0/12 What is its j-component? Submit Answer Tries 0/12

Explanation / Answer

at this time, v0y = 6.3 m/s

at maximum height, vy = 0

vf^2 - vi^2 = 2 a d

0^2 - 6.3^2 = 2 (-9.8)(d)

d = 2.025 m

Hmax = d + 8.7 = 10.725 m .....Ans

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to find its initial speed,

6.3^2 - v0y^2 = 2(-9.8)(8.7)

v0y = 14.5 m/s

v0x = 8 m/s

-14.5 = 14.5 - 9.8 t

t = 2.96 sec  

x = (8) (2.96 ) = 23.7 m . ......Ans

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vx = 8 m/s .....Ans

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vy = - 14.5 m/s .....Ans

{Speed = sqrt(vx^2 + vy^2) = 16.6 m/s

angle = tan^-1(vy/vx) = 61 deg }

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