(8c23p3) A cube with 1.40 m edges is oriented as shown in the figure in a region
ID: 1778961 • Letter: #
Question
(8c23p3) A cube with 1.40 m edges is oriented as shown in the figure in a region of uniform electric field. Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by 8.20i. (N*m(shift-6)2/C) 0.00 N*m 2/C You are correct. Your receipt no. is 153-2156 Previous Tries ) Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -3.00j 5.88 N*m 2/C You are correct. Your receipt no. is 153-9847 Previous Tries ) Find the electric flux through the right face if the electric field, in newtons per coulomb ( N/C), is given by -3.80i 6.00k 0.00 N*m 2/C You are correct. Previous Tries Your receipt no. is 153-672 What is the total flux through the cube for each of these fields? 0.00 N*mA2/C You are correct. Your receipt no. is 153-51846 Previous TriesExplanation / Answer
flux = E.A = E A cos(theta)
through right face:
A is along j vector and E is along i vector.
theta = 90 deg so cos90 = 0
flux = 0
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Through right face:
flux = (3) (1.40^2) cos180 = - 5.88 N m^2 / C
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A = 1.40^2 j
E.A = 0
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field is constant hence flux = 0
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