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A charge of +Q is fixed in space. A second charge of +q was first placed at a di

ID: 1872576 • Letter: A

Question

A charge of +Q is fixed in space. A second charge of +q was first placed at a distance r1 away from +Q. Then it was moved along a straight line to a new position at a distance R away from its starting position. The final location of +q is at a distance r2 from +Q

What is the change in the potential energy of charge +q during this process?

Qq/R

kQqR/r12

kQqR/r22

kQq((1/r2)-(1/r1))

kQq((1/r1)-(1/r2))

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Explanation / Answer

kQq((1/r2)-(1/r1))

change in potential energy = P.E.f - P.E.i
= kQq/r2 - kQq/r1  
=kQq((1/r2)-(1/r1))

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