15. -12 points SerCP10 6.P.033 My Notes Ask Your Teache A railroad car of mass 2

Question

15. -12 points SerCP10 6.P.033 My Notes Ask Your Teache A railroad car of mass 2.95 x 104 kg moving at 3.30 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s. (a) What is the speed of the three coupled cars after the collision? m/s (b) How much kinetic energy is lost in the collision? Need Help?Read It 16. -/1 points SerCP10 6.P.037 My Notes Ask Your Teache In a Broadway performance, an 76.0-kg actor swings from a R 3.95-m-long cable that is horizontal when he starts. At the bottom of his arc, he picks up his 55.0-kg costar in an inelastic collision. What maximum height do they reach after their upward swing? Need Help? Read

Explanation / Answer

Using conservation of momentum

Momentum of system before collision = momentum of system after Collision

mv1+ 2*mv2= (m + 2m) v

3.3+ 1.2= 3 v

V= 1.5 m/s

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Loss in energy

= 0.5*m ( v1^2+ 2* v2^2- 3* v^2)

= 0.5* 2.95*10^4* (3.3^2+ 2* 1.2^2- 3*1.5^2)

= 103545 J .

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Comment in case any doubt..goodluck

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