15. -12 points OSColPhys2016 25.6.WA.049 My Notes Ask Your Teacher You place a p

Question

15. -12 points OSColPhys2016 25.6.WA.049 My Notes Ask Your Teacher You place a photographic slide in front of a converging (convex) lens with a 2.59 cm focal length and it forms an image 14.0 cm from the slide. (a) If the image is real, determine the distance from the lens to the slide. Enter the smallest value first and the largest value second. If there is only one value, enter "none" for the smallest value. smallest value largest value cm cm (b) If the image is virtual, determine the distance from the lens to the slide. Enter the smallest value first and the largest value second. If there is only one value, enter "none" for the smallest value smallest value largest value cm cm Additional Materials Reading 16. 0/2 points| Previous Answers OSColPhys2016 25.7 WA 057 My Notes Ask Your The side mirrors on cars are convex mirrors. If the side mirror on the driver side of your car has a focal length with a magnitude of 7.00 m and a truck is at a distance of 3.00 m from the mirror, determine the following (a) image distance of the truck (Include the appropriate positive or negative sign.) 2.917 What is the relationship between the focal length, image distance, and object distance for a spherical mirror? m (b) magnification for this object distance (Include the appropriate positive or negative sign.) Additional Materials

Explanation / Answer

a) 1/ u + 1/v = 1/f

u + v = 14 cm

1/ ( 14-v) + 1/v =1/ 2.59

( 14 - v + v) / ( 14v -v^2) = 1/2.59

14/ (14v - v^2) = 1/2.59

14 x2.59 = 14v - v^2

v^2 - 14v + 36.26 =0

v= 14 + - sqroot ( 50.96) / 2=14+- 7.14/ 2= 10.57 , 3.43

u = 10.57, 3.43

b) 1/(7) = 1/ (-3) + 1/v

1/7 + 1/3 = 1/v

v = 2.1m

m = - v/u = - ( 2.1) / (-3) = 0.7

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