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The Expert TA I Human-l C Chegg Stucy | Guided Sc x ? > C ? ? secure l https://usq45tx.theexpertta.com/Common/lake lutorialAssi ::: Apps Enter Yor PN lus E sPN:Thc world R Facebook N Netfix a Amazon.com Onli A student MavMailH ·Become a Mcchanic D ACC Portal ? Fedex Express Salar Other bookmarks Class Management | Help HW14 Begin Date: 6272018 12:01:00 AM -Due Date: 2018 11:59:00 PM End Date: 79/2018 11:59:00 PM (690) Problem 15: Three children are riding on the edge of a merry-go-round that is a disk of mass 104 kg. radius 1.6 m. and is spinning at 19 rpm. The children have masses of 20.4 kg, 28.4 kg, and 34.6 kg. Randomnized Variables 14-104kg m - 20.4 kg M3-28.4 kg Assignment Status 34.6 kg Click here for detailed view f- 19 rpm DIf the child who has a mass of 28.4 kg moves to the center of the merry-go-round, what is the new magnitude of angular velocity in rpm? Grnde Summary 0% 100% Problem Status Potential 1 Completed 2 Completed 3 Completed 4 Copleted 5 Completed 6 Completed 7Completed 8 Completed 9 Completed 10 Completed sin cotan asin) tan() | ? | ( acos) coso) Attcmptscnaiuig: 10 (2% per atlanpi) detniled view atan acotan sho cosh tanhcotanh0 Degrees Radians Submi I give up! HInts: 2 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per teedback. How is Completed center? The children are small like point masses, but how o-roundl distributed? the mass of the mem- 12 Completed 13 Completed 14 Completed 133 AM O Type here to search MY TECH 1 844 662 4139 6/2018 2

Explanation / Answer

Given,

Mass m = 104 kg

Radius r = 1.6 m

Initial moment of inertia I1 = (104x1.6^2/2) + 1.6^2(20.4+28.4+34.6) = 346.624 kgm^2

Final moment of inertia I2 = (104x1.6^2/2) + 1.6^2(20.4 + 34.6) = 273.92 kgm^2

Using law of conservation of angular momentum

I1 w1 = I2 w2

Final angular velocity, w2 = (346.624 x 19)/273.92

w2 = 24.04 rpm (Ans)

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