The Expert TA I D × --) ? | Secure l https://usa08ct. rtta.com/Common/TakeTutori

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The Expert TA I D × --) ? | Secure l https://usa08ct. rtta.com/Common/TakeTutorialAssignment.aspx apter 21 Begin Date 3 292018 i20 0:00 AM (796) Problem i 4: In the circuit pictured, the resistors have values ofR,-155 R,-118 ?, and R,-138 ?, and the battery has an emf ? = 265 V. -Due Date: 4/12/2018 ii:59:00 PM End Date: 5/15/2018 11:59:00 PM , Otheexpertta.c 25% Part (a) write an expression for the current through the battery. 25% Part (b) in amperes, how much current ibar goes through the battery? 25% Part (c) Write an expression for the current through resistor 2. 25% Part (d) In amperes, what is the current 12 through resistor R2? - Potential 10 sin() | cos() | tan() | ?| (1117 819 cotan0 asin0 atan0 acotan0 sinh Attempts remaining (206 per attempt)

Explanation / Answer

(13)
(a) Person body will be in series with the internal resistance of the power battery .
therfore the net resistance will be
R = Rbody + Rinternal =  9.5*103 + 2000 = 11500 ohm
Hence from ohms law
V = IR
I = V/R = 20*103 /11500
I = 1.739 A
(b) Current in series remain same therfore the
power dissipiation in body = I2*(Rbody) = 1.7392*(9.5*103) = 28729.15 W
(c) If current (i) = 1.15*10-3 A
V = 20*103 volt
then V = IR
R =V/I = 20*103 /(1.15*10-3) = 17.39*106 ohm
R = 17.39 megaohm
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