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The connection shown is subjected to an axial for P. The maximum allowable shear

ID: 1861926 • Letter: T

Question

The connection shown is subjected to an axial for P. The maximum allowable shear stress of the two 13 mm diameter bolts is 30 MPa. The maximum allowable shear stress of the flat plate A is 26 MPa. What is the maximum force P that can be applied without the flat plate A or the pins failing due to shear stress?

The connection shown is subjected to an axial for P. The maximum allowable shear stress of the two 13 mm diameter bolts is 30 MPa. The maximum allowable shear stress of the flat plate A is 26 MPa. What is the maximum force P that can be applied without the flat plate A or the pins failing due to shear stress?

Explanation / Answer

force experienced in each pin = P/2

since each pin has 2 shear surface

so, shear stress in each pin = P /4 A (shear area ) = P / {pie * d(dia) ^2 /4 } = P / (pie * .013^2 /4 )

this shear should be less than allowable shear stress , equating to max limit

30 MPa = P / (pie * .013^2 /4 )

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