1. (2) A current of 0.25 amps is flowing trough a single resistor connected to a

1. R=V/I =48 Ohms 2. a) 90+60 =150 Ohm b)I=V/req =0.08A c)V1=0.08*90 =7.2 V d) 4.5 V e)I1*v1 =0.576 W f)0.08*4.5 =0.36 W ans

ID: 1860604 • Letter: 1

Question

1. (2) A current of 0.25 amps is flowing trough a single resistor connected to a 12.00 volt battery. Determine the

value of the resistor

2 .Two resistors R1 = 90.0 ohms and R2 = 60.0 ohms are connected in series to a 12.0 volt battery. Calculate the following:

a. (2) The equivalent resistance of the circuit.

b. (2) The current flowing in the circuit.

c. (2) The voltage drop or voltage measured across R1.

d. (2) The voltage drop or voltage measured across R2.

e. (2) The power or rate of energy dissipated through resistor R1.

f. (2) The power or rate of energy dissipated through resistor R2.

1. R=V/I

=48 Ohms

a) 90+60

=150 Ohm

b)I=V/req

=0.08A

c)V1=0.08*90

=7.2 V

d) 4.5 V

e)I1*v1

=0.576 W

f)0.08*4.5

=0.36 W ans

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