Assuming a Lithium-ion battery cell has 3.6V nominal cell voltage and 18 Ampere-

Question

Assuming a Lithium-ion battery cell has 3.6V nominal cell voltage and 18 Ampere-hour capacity. An EV battery pack consists of these Lithium-ion batteries with 10 parallel sets o f 70 series connected modules. Battery pack is connected to a traction motor. Assuming one motor motoring cycle (discharge of battery current) is shown in Fig. 1. Motor regenerative braking (charging battery) cycle is shown in Fig. 2. If regenerative braking is employed such that for every 50 motoring cycles there is 1 regenerative braking cycle, how much time (in hours) does it take to reach 80% DoD? (Note: In this problem, neglect variation o f capacity with discharge rate. Assume that the practical capacity is equal to the rated capacity.) Figure 1. Figure 2.

Explanation / Answer

for every 50 motoring cycle ,there is 1 regerative braking cycle

therefore

to reach 80% DOD ; we need first

Time for 80% DOD = 80% (1/2 * b *h) = 80% * 1/2 * 1.5 x 10-3 * 1 = 0.06 m sec

so we can write

for 50 motoring cycle ; 50 * (tim period of 1 motoring cycle) = 50 * 1.5 m sec = 75

so comparing

75 = 0.06 * 80% T

T= 75/(0.06*0.08)x10-6 = 0.15625 second

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