Assuming a Lithium-ion battery cell has 3.6V nominal cell voltage and 18 Ampere-

Question

Assuming a Lithium-ion battery cell has 3.6V nominal cell voltage and 18 Ampere-hour capacity. An EV battery pack consists of these Lithium-ion batteries with 10 parallel sets of 70 series connected modules. Battery pack is connected to a traction motor. Assuming one motor motoring cycle (discharge of battery current) is shown in Fig. 1. Motor regenerative braking (charging battery) cycle is shown in Fig. 2. What is the full-charged battery pack voltage and capacity (in Ampere-hour)? Suppose no regenerative braking is employed and battery energy storage capacity is reserved for motoring. How much time (in hours) does the battery take to reach 80% DoD (Depth of Discharge)? Figure 1.

Explanation / Answer

full charged battery pack voltage:?

in parallel voltage remains same and in series , the voltages adds up

so

3.6 V * 70 = 252 full charged battery pack voltage

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full charged battery pack current:?

batery capacity = 18 Ah

so full charged battery pack current will be 18 A for 1 hour

OR 1 Ampere for 18 hour

OR 9 Ampere for 2 Hour

OR 2 Ampere for 9 Hour

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Time for 80% DOD = 80% (1/2 * b *h) = 80% * 1/2 * 1.5 x 10-3 * 1

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