a 20-mm rod made of an experimental plastic is subjected to a tensile force of m

Question

a 20-mm rod made of an experimental plastic is subjected to a tensile force of magnitude P=6kN. Knowing that an elongation of 14 mm and a decrease in diameter of 0.85 mm are observed in a 150-mm length, determine the modulus of elasticity, the modulus of rigidity, and Poisson's Ration for the material. Also find the change in volume of the cylindrical rod, and the hydrostatic stress in the rod. Using the change in volume and the hydrostatic stress, calculate the bulk modulus of the material. And lastly, calculate the bulk modulus of the material using Young's Modulus and Poisson's Ratio.

I have found the following:
Modulus of Elasticity: 204.6MPa
Modulus of Rigidity: 70.30MPa
Poisson's Ratio: 0.455

Explanation / Answer

well poisson's ratio is a ratio : ( strain normal to applied load / strain parallel to applied load. So : Sx = 14/150 = 0.093 Sy= 0.85/20 = 0.0425 so v (poisson's ratio) = 0.0425/0.093= 0.457 E (modulus of elasticity) = engineering stress / engineerig strain engineering stress = 6000 N/ 314 = 19 MPa E= 19/0.093= 204 MPa

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