1. A waveform generator has been setup with a square wave output at 2.5kHz with

Question

1. A waveform generator has been setup with a square wave output at 2.5kHz with a 84% duty cycle.  If the peak-to-peak output amplitude has been set to 2.0V,  with an offset of 3.5V,  what is the minimum voltage of the output waveform? You can assume that the output impedance has been set correctly.

2.A waveform generator is loaded with a 50 Ohm resistor, and the resulting signal is measured with an oscilloscope.  What output impedance setting should the waveform generator use?

3. A waveform generator is used to supply one of the inputs for a 555 timer integrated circuit.  What output impedance setting should the waveform generator use?

4.A waveform generator is connected to an op-amp which has been setup as a voltage follower.  The voltage follower is then loaded with a 50 Ohm resistor.  What output impedance setting should the waveform generator use?

Explanation / Answer

1) Vpp = peak to peak voltage = 2 v

D = duty cycle =0.84 %

Voffset = 3.5 v

Vp = peak voltage = Vpp/2 = 1 v

V(min) = minimum voltage = -Vp + Voffset = -1 +3.5 = 2.5 v

2) impedance is 50 ohm

3) Vout = [ RL /(RL +Ro]*Vin

as Vout should be equal to Vin , then Ro = 0

Hence Ro = Output impedance = 0

4) Load impedance should match the output impedance , hence

   output impedance = 50 ohm

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