1. A uniform electric field of magnitude 375 N/C point- ing in the positive x-di

Question

1. A uniform electric field of magnitude 375 N/C point- ing in the positive x-direction acts on an electron, which is initially at rest. After the electron has moved 3.20 cm, what is (a) the work done by the field on the electron, (b) the change in potential energy associated with the electron, and (c) the velocity of the clectron? 7. M Oppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the mag- nitude of the force on an electron between the plates (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.90 mm from the positive plate

Explanation / Answer

a)

E = electric field = 375 N/C

q = magnitude of charge on electron = 1.6 x 10-19 C

magnitude of electric force on electron is given as

F = q E

F = (1.6 x 10-19) (375) = 6 x 10-17 N

d = distance moved = 3.20 cm = 0.032 m

work done is given as

W = F d Cos180

W = ( 6 x 10-17) (0.032) (-1) = - 1.92 x 10-18 J

b)

change in potential energy = W = - 1.92 x 10-18 J

c)

kinetic energy gained = magnitude of work done

(0.5) m v2 = W

(0.5) (9.1 x 10-31) v2 =  1.92 x 10-18

v = 2.1 x 106 m/s

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