1. A uniform disk of radius R is cut in half so that the remaining half has mass
ID: 2139860 • Letter: 1
Question
1. A uniform disk of radius R is cut in half so that the remaining half has mass M. (a)
What is the moment of inertia of this half about an axis perpendicular to its plane
through the point A? (b) What would be the moment of Inertia of a quarter of disk
with the mass M and radius R about an axis perpendicular to its plane through the
point B? (c) Calculate the moment of inertia of a uniform solid cone about an axis
through its center, assuming its mass is M, circular base radius is R and altitude h.
A uniform disk of radius R is cut in half so that the remaining half has mass M. (a) What is the moment of inertia of this half about an axis perpendicular to its plane through the point A? (b) What would be the moment of Inertia of a quarter of disk with the mass M and radius R about an axis perpendicular to its plane through the point B? (c) Calculate the moment of inertia of a uniform solid cone about an axis through its center, assuming its mass is M, circular base radius is R and altitude h.Explanation / Answer
(a) complete the disc for ease then I of both the equal parts will be equal as they are symmetric.
2I = (2M)R^2 /2
I = MR^2/2
(b) same approach as before
4I = (4M)R^2/2
I = MR^2/2
(c) 3MR^2/10
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