A certain semiconductor memory chip is specified as 2K times 8. How many words c

Question

A certain semiconductor memory chip is specified as 2K times 8. How many words can be stored on this chip? What is the word size? How many total bits can this chip store? Which memory stores the most bits: a 5M times 8 memory or a memory stores 1M words at a word size of 16 bits? A certain memory has a capacity of 4K x 8. How many data input and data output lines does it have? How many address lines does it have? What is its capacity in bytes? For the figure below which register will be enabled by the input address 1010

Explanation / Answer

part(a):

2K x 8 = 16 K.

1 word size =8 bits

then 16K/8 = 2048 words.

Total bits = 2*1024*8 = 16384 bits.

part(b):

5M x8 = 5*1024*1024*8 = 41,943,040 bits

1M x16 = 1*1024*1024*16 = 16,777,216 bits

Therefore 5M x 8 memory can store most bits.

part(c):

4K x 8 memory:

(a)No. of input/output lines = size of word = 8

(b) Address Lines = N where N is 2^N words in memory

2^N words = 4K words

Therefore N = 12 = Address Lines.

(c) Capacity in bytes = 1 Byte = 8 bits

Therefore 4k bytes = 4096 bytes

part(d) :

A3 A2 A1 A0 address lines corresponds to adress

1 0 1 0 .

where A1 and A0 corresponds to row select therefore A1A0 corresponds to "10" which is 2.

where A2 and A3 corresponds to column select therefore A1A0 corresponds to "10" which is 2.

Therefore row = 2 and column = 2 intersects at register 10.

I hope the answer satisfies your need and fulfilled your request.

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