A stone is thrown with an initial speed of 10.5 m/s at an angle of 55 degrees ab

Question

A stone is thrown with an initial speed of 10.5 m/s at an angle of 55 degrees above the horizontal from the top of a 39 m building. If g= 9.8 m/s^2 and air resistance is negligible, then what is the magnitude of the horizontal component of velocity as the rock strikes the ground?
A. 29 m/s

B. 15 m/s

C. 15 m/s

D. 6 m/s

E. 6 m/s

A stone is thrown with an initial speed of 10.5 m/s at an angle of 55 degree above the horizontal from the top of a 39 m building. If g = 9.8 m/s^2 and air resistance is negligible, then what is the magnitude of the horizontal component of velocity at the rock the ground?

Explanation / Answer

In projectile motion, there is no horizontal acceleration.

The horizontal component of velocity remains constant.

Vx=( vo)cos (55 degree) = (10.5 m/s)(cos55 degree)

=6.023 m/s

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