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It should be simple at least. I need to know how ~C+BC = (~C + B) Please show al

ID: 1833627 • Letter: I

Question

It should be simple at least. I need to know how ~C+BC = (~C + B)

Please show all the work and what properties you used. I've been trying to show how it is by using the identities but I can't seem to find out how. Please help. I'm trying to solve some boolean algebra questions but whenever i run into something with this form i get stuck. Yes i know that the two equations do equal each other, but that's not the point. Its bothering me that i don't know HOW it equals each other, and i hate to just memorize something that i should be understanding.

Thanks guys....

By the way ~C means NOT C.

Explanation / Answer

~C+BC = (~C + B)

= (~C+C) (~C+B)

= 1*(~C+B)

= (~C+B)

as u wanted

used property.

a +(bc) = (a + b)(a + c)   a(b + c) = ab + ac Distributivity

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