A wooden block of rectangular section 1.25 m wide, 2 m deep, 4m long floats hori

Question

A wooden block of rectangular section 1.25 m wide, 2 m deep, 4m long floats horizontally in sea water. If the specific gravity of wood is 0.64 and the water weighs 1025 kg(f)/m3 , find the volume of liquid displaced. Assume density of pure water = 1000
A wooden block of rectangular section 1.25 m wide, 2 m deep, 4m long floats horizontally in sea water. If the specific gravity of wood is 0.64 and the water weighs 1025 kg(f)/m3 , find the volume of liquid displaced. Assume density of pure water = 1000

Explanation / Answer

density of wooden block = specific gravity of wood * density of pure water = 0.64 * 1000 = 640kg/m3

volume of wooden block = 1.25*2*4 = 10m3

so weight of wooden block = density(*g) * volume = 640*10 = 6400N

Now, the trick comes

acc to archemedies principle = weight of water displaced = weight of material

so weight of watre displaced = 6400N

So,

Volume = 6400/1025= 6.24m^3.

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