A woman with mass of 58 kg stands at the rim of a horizontal table having a mome

Question

A woman with mass of 58 kg stands at the rim of a horizontal table having a moment of inertia of 430 kgm2 and a radius of 2.1 m. The turntable is initially at rest and is free to rotate about a frictionless, vertical axis through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.3 m/s relative to the Earth. With what angular speed does the turntable rotate? How much work does the woman do ON THE TABLE to set it into motion?

Explanation / Answer

solution
sory for inconvinience i used different numbers change and get exact ans
SINCE THEIR IS NO SLPPING BN women and table

1.So velocity = radius*angular velocity

1.5=2*w ==>
w=0.75 rads anticlockwise

2.Work done= change in KE of herself + Change in rotational KE of table


HERE iNERTIA (I) = 500 +(Mwomen*R^2) =760
W= (0.5*65*.75*.75 ) + (0.5*Inertia*w^2)

W =18.28 + (.5*760*.75*.75) W=232.03 Joules

Peter k the moment of INERTIA IS GIVEN BY MR^2 and not Mr

u have made that error please see

also the Angular velocity of women and table is same!!!
Please tell us all on what is NEGATIVE ENERGY!!!

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