Utilizing Figure 10.22, which is isothermal transformation diagram for an iron?c
ID: 1824629 • Letter: U
Question
Utilizing Figure 10.22, which is isothermal transformation diagram for an iron?carbon alloy of eutectoid composition), specify the nature of the final microstructure - in terms of microconstituents present and approximate percentages of each - of a small specimen that has been subjected to the following time?temperature treatments. In each case assume that the specimen begins at 760?C and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure.
(a) Cool rapidly to 700?C, hold for 104 s, then quench to room temperature.
(b) Rapidly cool to 600?C (1110?F), hold for 4 s, rapidly cool to 450?C (840?F), hold for 10 s, then quench to room temperature.
(c) Cool rapidly to 400?C (750?F), hold for 20 s, then quench to room temperature.
(d) Rapidly cool to 575?C (1065?F), hold for 20 s, rapidly cool to 350?C (660?F), hold for 100 s, then quench to room temperature.
(e) Rapidly cool to 250?C (480?F), hold for 100 s, then quench to room temperature in water. Reheat to 315?C (600?F) for 1 h and slowly cool to room temperature.
Please provide detailed solutions & explanations. Thank you.
Explanation / Answer
sol: solved it on other post just posting answers here a. After cooling and holding at 700°C for 104 s, approximately 50% of the specimen has transformed to coarse pearlite. Upon cooling to room temperature, the remaining 50% transforms to martensite. Hence, the final microstructure consists of about 50% coarse pearlite and 50% martensite. b. Heating to 700°C for 20 h the specimen in part (a) will transform the coarse pearlite and martensite to spheroidite. (c) Rapidly cool to 600°C (1110°F), hold for 4 s, rapidly cool to 450°C (840°F), hold for 10 s, then quench to room temperature. After cooling to and holding at 600°C for 4 s, approximately 50% of the specimen has transformed to pearlite (medium). During the rapid cooling to 450°C no transformations occur. At 450°C we start timing again at zero time; while holding at 450°C for 10 s, approximately 50 percent of the remaining unreacted 50% (or 25% of the original specimen) will transform to bainite. And upon cooling to room temperature, the remaining 25% of the original specimen transforms to martensite. Hence, the final microstructure consists of about 50% pearlite (medium), 25% bainite, and 25% martensite. d. After cooling to and holding at 400°C for 2 s, no of the transformation begin lines have been crossed, and therefore, the specimen is 100% austenite. Upon cooling rapidly to room temperature, all of the specimen transforms to martensite, such that the final microstructure is 100% martensite e After cooling and holding at 400°C for 20 s, approximately 40% of the specimen has transformed to bainite. Upon cooling to room temperature, the remaining 60% transforms to martensite. Hence, the final microstructure consists of about 40% bainite and 60% martensite.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.