A tank is divided into two parts by a partition. The volume of the tank is unkno

Question

A tank is divided into two parts by a partition. The volume of the tank is unknown. One side of the tank is evacuated and other side contains 0.03 m3 (meters cubed) of refrigerant-134a that is a saturated liquid at 1.2 MPa. The partition is now removed, and the refrigerant fills the entire tank. If the final state of the refrigerant is 303 K and 400 kPa, determine the volume of the tank.

**Please explain your steps in details

A tank is divided into two parts by a partition. The volume of the tank is unknown. One side of the tank is evacuated and other side contains 0.03 m3 (meters cubed) of refrigerant-134a that is a saturated liquid at 1.2 MPa. The partition is now removed, and the refrigerant fills the entire tank. If the final state of the refrigerant is 303 K and 400 kPa, determine the volume of the tank.

Explanation / Answer

given initial conditions of refrigerant(r)

Pi=1.2Mpa(saturated liquid)

volume (Vi)=.03m3

from property table

specific volume (vi)=vf (since saturated liquid)=.000893m3/kg

so mass of r=volume/sp.volume=33.59kg

now given final conditions are

Pf=400kpa,Tf=303k

so it is superheated vapour at this condition

from property table

sp.volume(vf)=.05662m3/kg

so total volume=m(vf)=.05662*33.59=1.9m3   (which is volume of the tank)

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